递等式计算.(1)149+587+51(2)85×0.75+15×75%(3)4×17×125(4)(+)×(5)(-)×45(6)[1-(×)]÷.

发布时间:2020-08-08 09:08:55

递等式计算.
(1)149+587+51
(2)85×0.75+15×75%
(3)4×17×125
(4)(+)×(5)(-)×45
(6)[1-(×)]÷.

网友回答

解:(1)149+587+51,
=149+51+587,
=200+587,
=787;
(2)85×0.75+15×75%,
=85×0.75+15×0.75,
=(85+15)×0.75,
=100×0.75,
=75;
(3)4×17×125,
=4×125×17,
=500×17,
=8500;
(4)(+)×,
=×,
=;
(5)(-)×45,
=×45-×45,
=15-9,
=6;
(6)[1-(×)]÷
=[1-]×3,
=1×3-×3,
=3-,
=.
解析分析:(1)可应用加法交换律进行计算即可得到
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