(2^2+1)(2^4+1)(2^8+1)(2^16+1)等于多少?
网友回答
用平方差公式
(2^2+1)(2^4+1)(2^8+1)(2^16+1)
=(2^2-1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)/(2^2-1)
=(2^4-1)(2^4+1)(2^8+1)(2^16+1)/3
=(2^8-1)(2^8+1)(2^16+1)/3
=(2^16-1)(2^16+1)/3
=(2^32-1)/3
======以下答案可供参考======
供参考答案1:
原式=5×17x257x65537
=1431655765