解方程(1)X+8×0.5=16???????(2)120%?x+3.2x=0.88????????(3)×(2.4x-50%)=??(4)=.

发布时间:2020-08-12 17:54:34

解方程
(1)X+8×0.5=16???????
(2)120%?x+3.2x=0.88????????
(3)×(2.4x-50%)=??
(4)=.

网友回答

解:(1)X+8×0.5=16,
???????????? x+4=16,
?????? ? ? x+4-4=16-4,
???????? ??????x=12,
????? ???? x÷=12÷,
????????? ?????? x=9;

(2)120%?x+3.2x=0.88,
?????? 1.2x+3.2x=0.88,
????????????4.4x=0.88,
?????? 4.4x÷4.4=0.88÷4.4,
?????????????? x=0.2;

(3)×(2.4x-50%)=,
???????????? 2.4x-0.5=÷,
???????? 2.4x-0.5+0.5=+0.5,
???????????????? 2.4x=1,
??????????? 2.4x÷2.4=1÷2.4,
??????????????????? x=;

(4)=,
?5x×1.6=12×7,
????? 8x=84,
???8x÷8=84÷8,
?????? x=10.5.
解析分析:(1)先按照运算顺序计算出8×0.5=4,等式两边再同时减去4得x=16-4,再同时除以;
(2)把120%化成小数1.2,先用乘法分配律算出左边=4.4x,等式两边再同时除以4.4;
(3)等式两边同时除以,把50%化成小数,得2.4x-0.5=÷,等式两边同时加0.5,再同时除以2.4;
(4)根据比例的基本性质得5x×1.6=12×7,即8x=12×7,等式两边再同时除以8.

点评:此题主要考查运用等式的基本性质或比例的基本性质解方程,要注意等号要对齐.
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