把下列各式分解因式: (1)1-100x² (2)-0.16+a²b²(

推荐回答

(1)1-100x² =(1+10x)(1-10x)(2)-0.16+a²b²=(ab)²-0.4²=(ab+0.4)(ab-0.4)(3)(a+b+c)²-(a-b-c)²=(a+b+c+a-b-c)(a+b+c-a+b+c)=2a(2b+2c)=4a(b+c)(4)9a²-(b-c)²=(3a+b-c)(3a-b+c)5)100p²-4q6=(10p)²-(2q³)²=(10p+2q³)(10p-2q³)=4(5p+q³)(5p-q³)(6)4(2x+y)²-9(x-2y)²=[2(2x+y)]²-[3(x-2y)]²=[2(2x+y)+3(x-2y]][2(2x+y)-3(x-2y]=[4x+2y+3x-6y][4x+2y-3x+6y]=(7x-4y)(x+8y)