4m的平方+n的平方-9分之1-4mn等于多少

其他回答

先配方，再平方差公式

解：根据题意

4m^2+n^2-1/9-4mn

=(4m^2-4mn+n^2)-1/9

=(2m-n)^2-(1/3)^2

=(2m-n+1/3)(2m-n-1/3)

4m²+n²-1/9-4mn

=(2m-n)²-1/9

=(6m-3n+1)(6m-3n-1)/9

4m^2+n^2-1/9-4mn

=(4m^2-4mn+n^2)-1/9

=(2m-n)^2-1/9

=(2m-n+1/3)(2m-n-1/3)

分解因式：

4m²+n²-1/9-4mn

=(2m-n)²-1/9

=(2m-n+1/3)(2m-n-1/3)

=(1/9)(6m-3n+1)(6m-3n-1)

4m^2+n^2-1/9-4mn=(2m-n)^2-1/9=(2m-n+1/3)(2m-n-1/3)