已知y=2^m+1,x=3+16^m,试用y的代数式表示x

网友回答

y=2^m+1,
2^m=y-1
m=log2[y-1]
把m带入x的表达式得
x=3+16^m
=3+16^{l0g2[y-1]}
=3+2^{4log2[y-1]}
=3+2^{log2[y-1]^4}
=3+(y-1)^4
所以 x=(y-1)^4+3
======以下答案可供参考======
供参考答案1:
2^m=y-1
x=3+16^m
=3+2^(4m)
=3+(y-1)^4
=y^4-4y^3+6y^2-4y+7