三角形与内接圆已知三角形的内接圆与AC,AB,BC,切于D,E,F且AB=5cm BC=9cm AC=6cm 求AE,BF和CD的长
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连接OA,OB,OC,OD,OE,OF
OE = OF 圆O为内切圆
==>BE = BF同理==>AE = AD,CD = CF
令 BF = x==>AE = 5-x,CF = 9-x;
==>CD = 1+x;
由 CD = CF
==>1+x = 9-x
==>x = 4==>AE = 1,BF = 4,CD = 5
======以下答案可供参考======
供参考答案1:
根据角平分线上的点到角两边的距离相等
cd=5bf=4ae=1