先化简再求值：(x2-x)/(x-1)*(x2-1)/(x2-2x+1)其中满足方程x2-3x+2=0
网友回答
x²-3x+2=0
(x-1)(x-2)=0
因为分母x-1≠0
所以x-2=0
x=2原式=x(x-1)/(x-1)*(x+1)(x-1)/(x-1)²
=x*(x+1)/(x-1)
=2*3/1
=6======以下答案可供参考======
供参考答案1:
=x(x-1)/x-1×(x+1)(x-1)/(x-1)²
=x/x-1
方程可化为 （x-1）（x-2）=0
X1=1 X2=2
代入x/x-1得
①1/1-1，，，，分母为0无意义
②2/2-1-2
OK了，，