计算：x³/(x+1)-x²+x-1（x+1）分之x的立方 减x的平方 加x 减1
网友回答
原式=x³/(x+1)-(x²-x+1)
=x³/(x+1)-(x+1)(x²-x+1)/(x+1)
=[x³-(x+1)(x²-x+1)]/(x+1)
=[x³-(x³+1)]/(x+1)
=-1/(x+1)
======以下答案可供参考======
供参考答案1:
x等于二分之一
供参考答案2:
原式=x³/(x+1)-(x²-x+1)
=x³/(x+1)-(x+1)(x²-x+1)/(x+1)
=[x³-(x+1)(x²-x+1)]/(x+1)
=[x³-(x³+1)]/(x+1)
=-1/(x+1)