矩形的周长是28cm,两边长为X,Y,若X^3+X^2Y-XY^2-Y^3=0,求矩形的面积
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X^3+X^2Y-XY^2-Y^3=0
X^2(X+Y)-Y^2(X+Y)=0
(X^2-Y^2)(X+Y)=0
(X-Y)(X+Y)^2=0
X=Y该矩形是正方形
边长：28÷4=7cm
面积：7*7=49cm^2
======以下答案可供参考======
供参考答案1:
x+y=28/2=14
x^3+x^2y-xy^2-y^3=0
x^2(x+y)-y^2(x+y)=0
(x^2-y^2)(x+y)=0
(x-y)(x+y)^2=0
x+y=14
x-y=0x=y=7所以矩形面积=49平方厘米