求下列各式极限.

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7原式=e^((x+2)ln((x-1)/(x+3))=e^((x+2)ln((1-1/x)/(1+3/x))=e^((x+2)ln((1-0)/(1+0))=e^0=18 原式=e^(xln((x^2)/(x^2-1))=e^(xln((1)/(1-1/x^2))=e^(xln((1)/(1-0))=e^0=1