3636/sin（π/2-a/2）=vt/sina,v为已知,求角a和角加速度.如题

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3636/sin(π/2-a/2)=3636/cos(0.5a)=vt/sina=vt/[(2sin0.5a)(cos0.5a)]
sin(0.5a)=vt/7272
a=2arcsin(vt/7272)+4kπ或a=(4k+2)π-2arcsin(vt/7272)
角加速度a'=14544/[√(7272²-v²t²)]或a'=-14544/[√(7272²-v²t²)]