(1)[5-3÷(1+2.25×)]÷12.5%
(2)[2-(8.25-5)×]÷0.9
(3)(20+12.56-31)÷299+(13-12.25)×1
(4)×(4.85÷-3.6+6.15×3)+1.75×(1+)+5.5
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解:(1)[5-3÷(1+2.25×)]÷12.5%,
=[5-3÷(1+)]÷12.5%,
=[5-3÷]÷12.5%,
=[5-]÷12.5%,
=×8,
=;
(2)[2-(8.25-5)×]÷0.9,
=[2-1.68×1.57]÷0.9,
=[2-2.6376]÷0.9,
=[-0.6376]÷0.9,
=-;
(3)(20+12.56-31)÷299+(13-12.25)×1,
=(20+12.56-31)÷299+1.15×1,
=(12.56-11)÷299+2.07,
=1.56÷299+2.07,
=+2,
=2;
(4)×(4.85÷-3.6+6.15×3)+1.75×(1+)+5.5,
=×(-3.6+)+1.75×2+5.5,
=×(-3+)+1.75×2+5.5,
=×(+)+3.5+5.5,
=×+9,
=+9,
=9.
解析分析:根据四则混合运算的法则:先算乘除后算加减,有括号的先算括号里的运算顺序计算即可.
点评:本题是比较复杂的四则混合运算,计算起来比较麻烦,注意为了减少计算量要随时约分.