解方程.
78x+4=82100÷100x=10x-+=9x-10-8x=105×8.5-10x=17.5(y+8)÷0.25=1003x+24=5x+23(y+3.5)×8=10y.
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解:(1)78x+4=82,
?????? 78x+4-4=82-4,
?????????? 78x=78,
?????? 78x÷78=78÷78,
?????????????x=1;
(2)100÷100x=10,
100÷100x×100x=10×100x,
??????????? 100=1000x,
????? 100÷1000=1000x÷1000,
??????????????x=0.1;
(3)x-+=,
?????? x-=,
???x-=;
??????????? x=1;
(4)9x-10-8x=10,
???????? x-10=10,
????? x-10+10=10+10,
??????????? x=20;
(5)5×8.5-10x=17.5,
?? 42.5-10x+10x=17.5+10x,
????? 42.5-17.5=17.5+10x-17.5,
???????????? 25=10x,
?????????25÷10=10x÷10,
????????????? x=2.5;
(6)(y+8)÷0.25=100,
(y+8)÷0.25×0.25=100×0.25,
????????????? y+8-8=25-8,
????????????????? y=17;
(7)3x+24=5x+23,
? 3x+24-3x=5x+23-3x,
???? 24-23=2x+23-23,
???????? 1=2x,
????? 1÷2=2x÷2,
???????? x=0.5;
(8)(y+3.5)×8=10y,
???????? 8y+28-8y=10y-8y,
?????????????? 28=2y,
??????????? 28÷2=2y÷2,
??????????????? y=14.
解析分析:(1)依据等式的性质,方程两边同时减4,再同时除以78求解,(2)依据等式的性质,方程两边同时乘100x,再同时除以1000求解,(3)先化简方程,再依据等式的性质方程两边同时加求解,(4)先化简方程,再依据等式的性质方程两边同时加10求解,(5)先化简方程,再依据等式的性质方程两边同时加10x,再同时减17.5,最后同时除以10求解,(6)依据等式的性质,方程两边同时乘0.25,再同时减8求解,(7)依据等式的性质,方程两边同时减3x,再同时减23,最后同时除以2求解,(8)先化简方程,再依据等式的性质,方程两边同时减8y,再同时除以2求解.
点评:本题主要考查学生依据等式的性质解方程的能力,解答时注意(1)对齐等号、(2)未知数由x、y的变化.