计算:(1)(-8a4b5c)÷(4ab5)?(3a3b2)(2)[2(a2x)3-9ax5]÷(3ax3)(3)(3mn+1)(-1+3mn)-(3mn-2)2(4

发布时间:2020-08-09 11:42:11

计算:
(1)(-8a4b5c)÷(4ab5)?(3a3b2)
(2)[2(a2x)3-9ax5]÷(3ax3)
(3)(3mn+1)(-1+3mn)-(3mn-2)2
(4)运用整式乘法公式计算1232-124×122
(5)[(xy+2)(xy-2)-2x2y2+4]÷(xy),其中x=10,y=-.

网友回答

解:(1)(-8a4b5c)÷(4ab5)?(3a3b2),
=-2a3c?(3a3b2),
=-6a6b2c;

(2)[2(a2x)3-9ax5]÷(3ax3),
=[2a6x3-9ax5]÷(3ax3),
=;

(3)(3mn+1)(-1+3mn)-(3mn-2)2,
=(9m2n2-1)-(9m2n2-12mn+4),
=9m2n2-1-9m2n2+12mn-4,
=12mn-5;

(4)1232-124×122,
=1232-(123+1)×(123-1),
=1232-(1232-1),
=1232-1232+1,
=1;

(5)[(xy+2)(xy-2)-2x2y2+4]÷(xy),
=[x2y2-4-2x2y2+4]÷(xy),
=(-x2y2)÷(xy),
=-xy;
当x=10,y=-时,原式=-10×(-)=.
解析分析:先根据整式的混合运算顺序和乘法公式分别进行化简,再代入求值即可.

点评:本题考查了整式的混合运算和乘法公式,在解题时要注意混合运算的顺序和简便方法的应用.
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