计算:2的n+3次方减16乘2的n次方除以2乘2的n+2次方因式分解 提公因式法。

网友回答

[2^(n+3)-16*2^n]÷2*2^(n+2)
=[2^(n+3)-(2^4)*2^n]÷2^(n+3)
=[2^(n+3)-2^(n+4)]÷2^(n+3)
=[2^(n+3)-2*2^(n+3)]÷2^(n+3)
=2^(n+3)(1-2)÷2^(n+3)
=-2^(n+3)÷2^(n+3)
=-1======以下答案可供参考======
供参考答案1:
麻烦把题目分解一下
供参考答案2:
没学过供参考答案3:
[2^(n+3)-16*2^n]/[2*2^(n+2)]
=[2^(n+3)-2^4*2^n]/[2^(n+3)]
=[ 2^(n+3)-2^(n+4)]/ [ 2^(n+3)]
=[2^(n+3)*(1-2)]/[2^(n+3)]
=[2^(n+3)]*(-1)/[2^(n+3)]
=-1供参考答案4:
16等于2的4次方，2的n+3次方减16乘2的n次方等于2的n+3次方减2的n+4次方等于负2的n+3次方；2乘2的n+2次方等于2的n+3次方。二者相除等于-1