计算:(1);(2)2x5?(2x-2y)2-(x3y2)2÷x5y2;(3)(m+n)(m2-mn+n2);(4)(2m+1-3n)(2m-1+3n).

发布时间:2020-08-06 10:14:58

计算:
(1);
(2)2x5?(2x-2y)2-(x3y2)2÷x5y2;
(3)(m+n)(m2-mn+n2);
(4)(2m+1-3n)(2m-1+3n).

网友回答

解:(1)=-1+2-1=0;
(2)2x5?(2x-2y)2-(x3y2)÷x5y2
=2x5?4x-4y2-x6y4÷x5y2
=8xy2-xy2
=7xy2;
(3)(m+n)(m2-mn+n2)
=m3-m2n+mn2+m2n-mn2+n3
=m3+n3;
(4)(2m+1-3n)(2m-1+3n)
=(2m)2-(1-3m)2
=4m2-(1-6n+9n2)
=4m2-1+6n-9n2.
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