sin(-1920°)=?cos(-1560°)=?tan(-17π/6)=?

发布时间:2021-02-19 21:17:05

sin(-1920°)=?cos(-1560°)=?tan(-17π/6)=?

网友回答

sin(-1920º)=- sin1920º=-sin(1800º+120º)=-sin120 º=-sin(180º-60º)=-sin60º=-√3/2;
cos(-1560°)= cos1560°=cos(1800º-240º)=cos240º=cos(180º+60º)=-cos60º=-1/2;
tan(-17π/6)=- tan17π/6=-tan(2π+5π/6)=-tan5π/6=-tan(π-π/6)=tanπ/6=√3/3.
======以下答案可供参考======
供参考答案1:
-1920=360*(-5)-120
sin(-120)=-sin(120)=-sin60==
-1560=360*(-4)-120
cos(-120)=cos120=-cos60==
-17π/6=π*(-3)+1/6π
tan(1/6π)=tan(30)==
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