已知△ABC≌△DEF,角A=85度,角DEF=60° ,AB=8,EH=5,求角DFE的度数及DH的长
网友回答
∠DFE=35°
DH=3∵△ABC≌△DEF,∠A=85°,AB=8
∴∠D=∠A=85°,DE=AB=8
∵∠DEF=60°,∠DFE+∠DEF+∠D=180°
∴∠DEF=180°-85°-60°=35°
∵EH=5∴DH=DE-EH=8-5=3
======以下答案可供参考======
供参考答案1:
DFE=180°-60°-85°=35°
AB=DE=8
DH=8-5=3