三角形内角和应用题如图,已知：∠A= 1/2∠ABC = 1/2∠C,BD平分∠ABC,求∠DBC的

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∵∠A+∠ABC+∠C=180°
又∵∠A= 1/2∠ABC = 1/2∠C
∴1/2∠ABC+∠ABC+∠ABC=180°
∴∠ABC=72°
∵BD平分∠ABC
∴∠ABD=∠CBD=1/2∠ABC=36°
======以下答案可供参考======
供参考答案1:
∵∠A+∠ABC+∠C=180°
又∵∠A= 1/2∠ABC = 1/2∠C
∴1/2∠ABC+∠ABC+∠ABC=180°
∴∠ABC=72°
∵BD平分∠ABC
∴∠ABD=∠CBD=1/2∠ABC=36°
供参考答案2:
∵∠A+∠ABC+∠C=180°
又∵∠A= 1/2∠ABC = 1/2∠C
∴1/2∠ABC+∠ABC+∠ABC=180°
∴∠ABC=72°
∵BD平分∠ABC
∴∠ABD=∠CBD=1/2∠ABC=36°
供参考答案3:
∵∠A+∠ABC+∠C=180°
又∵∠A= 1/2∠ABC = 1/2∠C
∴1/2∠ABC+∠ABC+∠ABC=180°
∴∠ABC=72°
∵BD平分∠ABC
∴∠ABD=∠CBD=1/2∠ABC=36°
供参考答案4:
∵∠A+∠ABC+∠C=180°
又∵∠A= 1/2∠ABC = 1/2∠C
∴1/2∠ABC+∠ABC+∠ABC=180°
∴∠ABC=72°
∵BD平分∠ABC
供参考答案5:
∵∠A= 1/2∠ABC = 1/2∠C
∴∠ABC=∠C=2∠A
∵∠A+∠ABC +∠C=180°
∴∠A+2∠A+2