求未知数X:6.72-1.2X=1.44??????????????4×(X+18)=6×(X-14)4513-x=2x+212=3.25??????????????

发布时间:2020-08-06 14:45:59

求未知数X:6.72-1.2X=1.44??????????????4×(X+18)=6×(X-14)4513-x=2x+212=3.25???????????????????x+(123+16?)=4.5?????????????????????578+x=9.

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解:(1)6.72-1.2x=1.44,
?? ?6.72-1.2x+1.2x=1.44+1.2x,
???????? 6.72-1.44=1.44+1.2x,
???????? 1.2x÷1.2=5.28÷1.2,
???????????????? x=4.4;

(2)4×(x+18)=6×(x-14),
?????????? 4x+72=6x-84,
??????? 4x+72-4x=6x-84-4x,
????????????? 72=2x-84,
????????2x-84+84=72+84,
?????????? 2x÷2=156÷2,
?????????????? x=78;

(3)4513-x=2,
?? 4513-x+x=2+x,
???? 4513-2=2+x-2,
????????? x=4511;

(4)x+212=3.25,
?x+212-212=3.25-212,
???????? x=-208.75;

(5)x+(123+16)=4.5,
????????????x+139=4.5,
??????? x+139-139=4.5-139,
???????????? x=-134.5;

(6)578+x=9,
?578+x-578=9-578,
???????? x=-569.
解析分析:(1)根据等式的性质,在方程两边同时加上1.2x,再减去1.44,最后除以1.2求解,
(2)先化简,再根据等式的性质,在方程两边同时减去4x,再加上84,最后除以2求解,
(3)根据等式的性质,在方程两边同时加上x,再减去2求解,
(4)根据等式的性质,在方程两边同时减去212求解,
(5)先化简,再根据等式的性质,在方程两边同时减去139求解,
(6)根据等式的性质,在方程两边同时减去578求解,

点评:本题考查了学生根据等式的性质解方程的能力,注意等号对齐.
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