x的2次方-xy-2y的2次方分之x的2次方+2xy+y的2次方怎么化简?

网友回答

(x^2+2xy+y^2)/(x^2-2xy+y^2 )
=((x+y)^2）/(x+y)(x-y)
=(x+y)/(x-y)
======以下答案可供参考======
供参考答案1:
X2+XY‐2Y+Y2
供参考答案2:
(x^2+2xy+y^2)/(x^2-2xy+y^2 )
=((x+y)^2）/(x+y)(x-y)
=(x+y)/(x-y）
x/y=1/2
那么y=2x上式等于-3
供参考答案3:
已知x/y=1/2，求(x²+2xy+y²)/(x²-xy-2y²)的值
(x²+2xy+y²)/(x²-xy-2y²)(分子分母同除以xy；将x/y=1/2，y/x=2代入)
=[(x/y)+2+(y/x)]/[(x/y)-1-2(y/x)]=[(1/2)+2+2]/[(1/2)-1-4]=(9/2)/(-9/2)=-1.