计算（2-1)(2+1)(2²+1)(2的四次方+1)(2的八次方+1)

网友回答

(x-y)(x+y)=x^2-y^2
(2-1)(2+1)=2^2-1
(2^2-1)(2^2+1)=2^4-1
(2^4-1)(2^4+1)=2^8-1
(2^8-1)(2^8+1)=2^16-1
======以下答案可供参考======
供参考答案1:
2-1)(2+1)(2²+1)(2的四次方+1)(2的八次方+1)
=(2^2-1)(2^2+1)(2^4+1)(2^8+1)
=(2^4-1)(2^4+1)(2^8+1)
=(2^8-1)(2^8+1)
=2^16-1
供参考答案2:
（2-1)(2+1)(2^2+1)(2^4+1)(2^8+1)
=(2^2-1)(2^2+1)(2^4+1)(2^8+1)
=(2^4-1)(2^4+1)(2^8+1)
=(2^8-1)(2^8+1)
=2^16-1
=65535
供参考答案3:
原式＝1×3×5×17×257
＝65535
蓝木连