解下列方程①根号3x+根号2=根号2x+根号3②根号2(根号2-x)+x=根号2

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①根号3x+根号2=根号2x+根号3
根号3x-根号2x=根号3-根号2 (两边平方有)
3x+2x-2根号6*x=5-2根号6
x=(5-2根号6)/(5-2根号6)=1
②根号2(根号2-x)+x=根号2
2-根号2*x+x=根号2
(1-根号2)x=根号2-2=根号2(1-根号2)
x=根号2======以下答案可供参考======
供参考答案1:
解:(1)√3x＋√2=√2x＋√3
(√3-√2)x=√2-√3
x=-1 (2)√2(√2-x)＋x=√2
2-√2x＋x=√2
(1-√2)x=√2-2
(1-√2)x=√2(1-√2)
x=√2。供参考答案2:
(1)√3x＋√2=√2x＋√3
(√3-√2)x=√3-√2
x=1(2)：√2(√2-x) x=√2
解 ：2-√2x x=√2
x(1-√2)=√2-2
x=√2