求y=ln√1-x^3的微分如题.

网友回答

y = ln√(1-x³)
= (1/2)ln(1-x³)
dy/dx = (1/2) * 1/(1-x³) * (-3x²)
= -3x²/[2(1-x³)]
= 3x²/[2(x³-1)]
dy = {3x²/[2(x³-1)]}dx