∫sint/(cost+sint)dt

发布时间:2021-02-25 19:00:41

∫sint/(cost+sint)dt

网友回答

∫sint/(cost+sint)dt
= (1/2)∫[(sint+cost) +(sint-cost) ]/(cost+sint)dt
=(1/2)∫ dt + (1/2)∫(sint-cost)/(cost+sint)dt
=(1/2)∫ dt - (1/2)∫dln(sint+cost)
=(1/2)t - (1/2)ln|sint+cost| + C
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