求函数y=2sin(2x-π/6)的值域,单调区间,对称轴,对称点,

网友回答

1.当2x-π/6=π/2+2kπ,即当x=π/3+kπ,(k∈Z)时,ymax=2×1=2,当2x-π/6=3π/2+2kπ,即x=5π/6+kπ,(k∈Z)时,ymin=2×(-1)=-2,∴值域[-2,2].2.由-π/2+2kπ≤2x-π/6≤π/2+2kπ,得-π/6+kπ≤x≤π/3+kπ,k∈Z,单增...