用分组分解法分解因式X^2+2Y-XY-2X8A^3-12A^2B-6A^2C+9ABCMNP^2-

发布时间:2021-03-07 21:01:32

用分组分解法分解因式X^2+2Y-XY-2X8A^3-12A^2B-6A^2C+9ABCMNP^2-MNQ^2-M^2PQ+N^2PQ

网友回答

X^2+2Y-XY-2X
=(X^2-2X)-(XY-2Y)
=X(X-2)-Y(X-2)
=(X-Y)(X-2)
8A^3-12A^2B-6A^2C+9ABC
=(8A^3-12A^2B)-(6A^2C-9ABC )
=4A^2(2A-3B)-3AC(2A-3B)
=A(4A-3C)(2A-3B)
MNP^2-MNQ^2-M^2PQ+N^2PQ
=(MNP^2-M^2PQ)-(MNQ^2-N^2PQ)
=MP(NP-MQ)-NQ(MQ-NP)
=(MP+NQ)(NP-MQ)
======以下答案可供参考======
供参考答案1:
X^2+2Y-XY-2X
=X(X-2)-Y(X-2)=(X-Y)(X-2)供参考答案2:
X^2+2Y-XY-2X
=(X^2-2X)-(XY-2Y)
=X(X-2)-Y(X-2)
=(X-2)(X-Y)
8A^3-12A^2B-6A^2C+9ABC
=A(8A^2-12AB-6AC+9BC)
=A[4A(2A-3B)-3C(2A-3B)]
=A(2A-3B)(4A-3C)
MNP^2-MNQ^2-M^2PQ+N^2PQ
=(MNP^2-M^2PQ)-(MNQ^2-N^2PQ)
=MP(NP-MQ)-NQ(MQ-NP)
=(NP-MQ)(MP+NQ)
供参考答案3:
1.X^2+2Y-XY-2X= (x^2-2x)+(2y-xy)=x(x-2)+y(2-x)=(x-y)(x-2)
2.8A^3-12A^2B-6A^2C+9ABC
=A[8A^2-12AB-6AC+9BC]
=A[4A(2A-3B)-3C(2A-3B)]
=A(2A-3B)(4A-3C)
3.MNP^2-MNQ^2-M^2PQ+N^2PQ
=mnp^2+n^2pq-(mnq^2+m^2pq)
=np(mp+nq)-mq(nq+mp)
(mp+nq)(np-mq)
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