计算:(x2-2x+1-y2)÷(x+y-1)=________.

发布时间:2020-07-30 12:08:55

计算:(x2-2x+1-y2)÷(x+y-1)=________.

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x-y-1
解析分析:先对(x2-2x+1-y2)进行因式分解得:(x2-2x+1-y2)=(x-1+y)(x-1-y),再去相除得即可求出结果.

解答:(x2-2x+1-y2)÷(x+y-1),=(x-1+y)(x-1-y)÷(x+y-1),=x-y-1.故应填:x-y-1.

点评:主要考查多项式除法运算,先把被除式进行因式分解是解题的关键,也是难点.
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