log(2)2/3+log(2)6+log(4)8=

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log(2)2/3+log(2)6+log(4)8
= log(2)2/3+log(2)6+log(2²)8
= log(2)2/3+log(2)6+1/2log(2)8
=log(2)2/3+log(2)6+log(2)(2√2)
=log(2)(2/3×6×2√2)
=log(2)(8√2)
=log(2)(2^7/2)
=7/2这是我在静心思考后得出的结论,
如果不能请追问,我会尽全力帮您解决的~
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======以下答案可供参考======
供参考答案1:
log(2)2/3+log(2)6+log(4)8
=log(2) [(2/3)*6] + (1/2)*log(2) 8
=log(2) 4 + (1/2)*3
=2+ 3/2
=7/2