填空(x-y)(x2+xy+y2)=________;(x-y)(x3+x2y+xy2+y3)=________
根据以上等式进行猜想,当n是偶数时,可得:(x-y)(xn+xn-1y+yn-2y2+…+x2yn-2+xyn-1+yn)=________.
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x3-y3 x4-y4 xn+1-yn+1
解析分析:根据多项式与多项式相乘的法则:多项式与多项式相乘,先用一个多项式的每一项乘另外一个多项式的每一项,再把所得的积相加.
解答:原式=x3+x2y+xy2-x2y-xy2-y3=x3-y3;
故