lingo不太会,现在想将一个整数规划改成lingo,已知数据zuhe（22*3的一个矩阵）：0\x

网友回答

sets:s1/1..22/:x;
s2/1..3/:;
s12(s1,s2):zuhe;
endsets
data:!自己加数据;
enddata
[email protected](s1:x);
@sum(s1(i):x(i)*zuhe(i,1))>=100;@sum(s1(i):x(i)*zuhe(i,2))>=68;@sum(s1(i)|i#le#5:x(i))[email protected](s1(i)|i#ge#6#and#i#le#10:x(i));
@sum(s1(i)|i#ge#11#and#i#le#16:x(i))[email protected](s1(i)|i#ge#17:x(i));
@for(s1:@gin(x));