拆（添）项法,x^3-7x^2+6和x^3-9x^2+26x第二个是x^3-9x^2+26x+24，
网友回答
x^3-7x^2+6=x^3-x^2--6x^2+6=(x^3-x^2)-(6x^2-6)
=x^2(x-1)-6(x+1)(x-1)=(x-1)(x^2-6x-6)
======以下答案可供参考======
供参考答案1:
x^3-7x^2+6 = x^3-x^2 -6x^2+6 =x^2(x-1) -6(x-1)(x+1)=...
x^3-9x^2+26x+24 =x^3-9x^2+26x+24好像分解不开