①[3.2×(1-58 )+335]×2112 ②137+2415+447+3215③4397×99 ④1.8×25%+2.2×25%
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解:①[3.2×(1-58 )+335]×2112,
=[3.2×1-3.2×58+335]×2112,
=[3.2-185.6+335]×2112,
=[3.2+335-185.6]×2112,
=152.6×2112,
=322291.2;
②137+2415+447+3215,
=(137+447)+(2415+3215),
=584+5630,
=6214;
③4397×99,
=4397×(100-1),
=4397×100-4397,
=439700-4397,
=435303;
④1.8×25%+2.2×25%,
=(1.8+2.2)×0.25,
=4×0.25,
=1.
解析分析:①先去括号,然后把3.2-185.6+335转化为3.2+335-185.6,计算完括号的,再算括号外的乘法;
②运用加法交换律和加法结合律进行简算;
③先把99改写为100-1,然后运用乘法分配律进行简算;
④运用乘法分配律简算.
点评:本题考查了整数、小数的四则混合运算顺序,同时也考查了运算定律的运用.