(2²+1)(2&sup4+1)(2&sup8+1)(2&sup16+1)(2&sup32

发布时间：2021-02-26 19:14:05

(2²+1)(2&sup4+1)(2&sup8+1)(2¹6+1)(2³2+1)

网友回答

令A=上式,则
(2^2-1)A
=(2^2-1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)
=(2^4-1))(2^4+1)(2^8+1)(2^16+1)(2^32+1)
=(2^8-1)(2^8+1)(2^16+1)(2^32+1)
=(2^16-1)(2^16+1)(2^32+1)
=(2^32-1)(2^32+1)
=2^64-1
A=(2^64-1)/3
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