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已知(x-ax)8展开式中常数项为1120.其中实数a是常数.则展开式中各项系数的和是1或
已知(x-ax)8展开式中常数项为1120.其中实数a是常数.则展开式中各项系数的和是1或
发布时间:2021-02-20 21:58:04
(2010•南宁二模)已知(x-ax)8展开式中常数项为1120,其中实数a是常数,则展开式中各项系数的和是1或6561
1或6561
.
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答案:
分析:
利用二项展开式的通项公式求出第r+1项,令x的指数为0得常数项列出方程求出a,给二项式中的x 赋值求出展开式中各项系数的和.
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