arcsinx+arctg1/7=π/4,则x=

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arcsinx+arctg1/7=π/4
tan(arcsinx+arctg1/7)=tan(π/4)=1
〔tan(arcsinx)+tan(arctg1/7)〕/
（1-tan(arcsinx)tan(arctg1/7)〕=1；
tan(arcsinx)+tan(arctg1/7)
=1-tan(arcsinx)tan(arctg1/7)
tan(arcsinx)+1/7=1-1/7 tan(arcsinx)
8tan(arcsinx)=6
tan(arcsinx)=3/4
令arcsinx=a,则sina=x
原式化简为：tana=3/4,
x=sina=3/5.
======以下答案可供参考======
供参考答案1:
arcsinx=x
arctg1/7=1/7
x=π/4-1/7
供参考答案2:
arcsinx=x
arctg1/7=1/7
x=π/4-1/7
arcsinx+arctg1/7=π/4
tan(arcsinx+arctg1/7)=tan(π/4)=1
〔tan(arcsinx)+tan(arctg1/7)〕/
（1-tan(arcsinx)tan(arctg1/7)〕=1；
tan(arcsinx)+tan(arctg1/7)
=1-tan(arcsinx)tan(arctg1/7)
tan(arcsinx)+1/7=1-1/7 tan(arcsinx)
8tan(arcsinx)=6
tan(arcsinx)=3/4
令arcsinx=a,则sina=x
原式化简为：tana=3/4,
x=sina=3/5.