-X/(X+3)(X-5)=A/(X+3)+B/(X-5) 求A B 的值 初二分式内容-X+13/(X+3)(X-5)=A/(X+3)+B/(X-5) 求A B 的值 初二分式内容
网友回答
右边通分=[A(X-5)+B(X+3)]/(X+3)(X-5)
=[(A+B)X+(3B-5A)]/(X+3)(X-5)
=(-X+13)/(X+3)(X-5)
所以(A+B)X+(3B-5A)=-X+13
则A+B=-1
3B-5A=13
解得A=1,B=-2
======以下答案可供参考======
供参考答案1:
A = -2 B = 1
供参考答案2:
将等式通分后可得：（-X+13）/(X+3)(X-5)=[(A+B)X+(3B-5A)]/(X+3)(X-5)
由此可得：A+B=-1
3B-5A=13
解得：A=-2，B=1