因式分解：2a（a+b)的平方-8ab的平方 计算：m-2+(m-2)分之1

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2a(a+b)^2-8ab^2
=2a(a^2+2ab+b^2)-8ab^2
=2a^3+4a^2b+2ab^2-8ab^2
=2a^3+4a^2b-6ab^2
=2a(a^2+2ab-3b^2)
=2a(a+3b)(a-b)
m-2+1/(m-2)
=(m-2)^2/m-2+1/(m-2)
=[(m-2)^2+1]/(m-2)
=(m^2-4m+4+1)/(m-2)
=(m^2-4m+5)/(m-2) (b^2-4ab
======以下答案可供参考======
供参考答案1:
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