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当x1>0.x2>0.则x1+x22≥x1x2.当且仅当x1=x2时取等号.这个结论可以推
当x1>0.x2>0.则x1+x22≥x1x2.当且仅当x1=x2时取等号.这个结论可以推
发布时间:2021-02-20 14:46:53
当x1>0,x2>0,则x1+x22≥
x1x2,当且仅当x1=x2时取等号,这个结论可以推广到n个正数的情况,即:当x1>0,x2>0,…,xn>0,则x1+x2+x3+…+xnn≥nx1x2x3…xn
(n∈N*)
x1+x2+x3+…+xnn≥nx1x2x3…xn
(n∈N*)
;当且仅当x1=x2=x3=…=xn(n∈N*)
x1=x2=x3=…=xn(n∈N*)
时取等号.
网友回答
答案:
分析:
认真观察
x1+x2
2
≥
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