计算(1)(2)(3)0.03(4)(5){[4-]}×.

发布时间:2020-08-10 05:55:19

计算
(1)
(2)
(3)0.03
(4)
(5){[4-]}×.

网友回答

解:(1),
=3×(1.25×2.5×0.4×8),
=3×[(1.25×8)×(2.5×0.4)],
=3×(10×1),
=3×10,
=;

(2),
=35×29+65×29-×29,
=(35+65-)×29,
=101×29,
=(100+1)×29,
=100×29+1×29,
=2900+29,
=2929;

(3)0.03,
=0.03÷[(14-1.2)÷0.6],
=0.03÷[12.8÷0.6],
=0.03÷,
=;

(4),
=2×0.65+2×0.35-3.12÷2,
=2×(0.65+0.35)-3.12÷2,
=2×1-3.12÷2,
=2-1,
=1;

(5){[4-]}×,
={[4-(×3.5-×3.5)]}×,
={[4-(7.5-4.2)]}×,
={[4-3.3]}×,
={0.7}×,
={-}×,
=×,
=×-×,
=-,
=.
解析分析:(1)先把3.2分解成8×0.4,再运用乘法结合律简算;
(2)先把除法变成乘法,然后两次运用乘法分配律简算;
(3)先算小括号里面的乘法,再算小括号里面的减法,然后算中括号里面的除法,最后算括号外的除法;
(4)先算小括号里面的加法,再运用乘法分配律简算;
(5)先运用乘法分配律计算中括号里面的运算,再算大括号里面的除法,然后算大括号里面的减法,最后再运用乘法分配律简算.

点评:本题计算较复杂,要注意分析式中数据,运用合适的简便方法计算.
以上问题属网友观点,不代表本站立场,仅供参考!