m²-1分之m²-2m+1÷(m+1分之m-1-1+m)
网友回答
原式=(m-1)²/(m+1)(m-1)÷[(m-1)-(m+1)²]/(m+1)
=(m-1)/(m+1)×(m+1)/(-m²-m-2)
=-(m-1)/(m²+m+2)
======以下答案可供参考======
供参考答案1:
=(m-1)²/(m+1)(m-1) ÷[(m-1)+(m+1)(m-1)]/(m+1)
=(m-1)/(m+1)×(m+1)/m(m-1)
=1/m供参考答案2:
您好 m²-1分之m²-2m+1÷(m+1分之m-1-1+m)(图1)
答题不易,望采纳O(∩_∩)O谢谢
供参考答案3:
m²-1分之m²-2m+1÷(m+1分之m-1-1+m)
=(m-1)²/(m+1)(m-1)÷[(m-1)-(m+1)²]/(m+1)=(m-1)/(m+1)×(m+1)/(-m²-m-2)=-(m-1)/(m²+m+2)
满意请采纳,谢谢!【姜永哲11】