计算.
(1)(-6)×(+8);
(2)(-0.36)×(-);
(3)(-2)×(-2);
(4)(-288)×0;
(5)2×(-1)×(-)×(-);
(6)(-5)×(-8)×0×(-10)×(-15);
(7)(-3)×(-0.12)×(-2)×33;
(8)(+)×|-|×2×(-5);
(9)(-3)×(-4)×(-5)+(-5)×(-7);
(10)(-0.1)×(-1)×(-100)-0.01×(1000).
网友回答
解:(1)(-6)×(+8),
=-(6×8),
=-48;
(2)(-0.36)×(-),
=0.36×,
=0.04×2.
=0.08;
(3)(-2)×(-2),
=×,
=6;
(4)(-288)×0=0;
(5)2×(-1)×(-)×(-),
=-×××,
=-3;
(6)(-5)×(-8)×0×(-10)×(-15)=0;
(7)(-3)×(-0.12)×(-2)×33,
=-×0.12××,
=-30;
(8)(+)×|-|×2×(-5),
=×××(-),
=-4;
(9)(-3)×(-4)×(-5)+(-5)×(-7),
=-3×4×5+5×7,
=-60+35,
=-25;
(10)(-0.1)×(-1)×(-100)-0.01×(1000),
=-0.1×1×100-0.01×1000,
=-10-10,
=-20.
解析分析:根据有理数的乘法法则进行运算,先判断出积的符号,再计算绝对值.
点评:此题考查了有理数的运算法则:①运用乘法法则,先确定符号,再把绝对值相乘.
②多个因数相乘,看0因数和积的符号当先,这样做使运算既准确又简单.