1^+2^+3^+4^+.=(这里的^指平方)1^+2^+3^+4^+.=(这里的^指三次方)注意!

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(n+1)^3-n^3=3n^2+3n+1
n^3-(n-1)^3=3(n-1)^2+3(n-1)+1
…… 2^3-1^3=3*1^2+3*1+1
相加 (n+1)^3-1=3*(1^2+2^2+……+n^2)+3*(1+2+……+n)+n*1
(n+1)^3-1=3*(1^2+2^2+……+n^2)+3*n(n+1)/2+n
1^2+2^2+……+n^2=[(n+1)^3-3n(n+1)/2-(n+1)]/3
=(n+1)(n^2+2n+1-3n/2-1)/3
=(n+1)(2n^2+n)/6
=n(n+1)(2n+1)/6
2、1^3+2^3+.+n^3=n^2(n+1)^2/4=[n(n+1)/2]^2
(n+1)^4-n^4=[(n+1)^2+n^2][(n+1)^2-n^2]
=(2n^2+2n+1)(2n+1)
=4n^3+6n^2+4n+1
2^4-1^4=4*1^3+6*1^2+4*1+1
3^4-2^4=4*2^3+6*2^2+4*2+1
4^4-3^4=4*3^3+6*3^2+4*3+1
.(n+1)^4-n^4=4*n^3+6*n^2+4*n+1
各式相加有 (n+1)^4-1=4*(1^3+2^3+3^3...+n^3)+6*(1^2+2^2+...+n^2)+4*(1+2+3+...+n)+n
4*(1^3+2^3+3^3+...+n^3)=(n+1)^4-1+6*[n(n+1)(2n+1)/6]+4*[(1+n)n/2]+n
=[n(n+1)]^2
1^3+2^3+...+n^3=[n(n+1)/2]^2
2、