(m2-2m+1)/（m2-1)÷（(m-1)-（m-1）/（m+1））,其中m=根号3

网友回答

(m^2-2m+1)/（m^2-1)÷[(m-1)-(m-1)/(m+1)]=(m-1)^2/(m-1)(m+1)÷[(m-1)(m+1)/(m+1)-(m-1)/(m+1)]=(m-1)/(m+1)÷[(m^2-1)/(m+1)-(m-1)/(m+1)]=(m-1)/(m+1)÷{[(m^2-1-(m-1)]/(m+1)}=(m-1)/(m+1)÷{[m^2-1-m+1)]/(m+1...
======以下答案可供参考======
供参考答案1:
(m^2-2m+1)/（m^2-1)÷[(m-1)-(m-1)/(m+1)]
=(m-1)^2/(m-1)(m+1)÷[(m-1)(m+1)/(m+1)-(m-1)/(m+1)]
=(m-1)/(m+1)÷[(m^2-1)/(m+1)-(m-1)/(m+1)]
=(m-1)/(m+1)÷{[(m^2-1-(m-1)]/(m+1)}
=(m-1)/(m+1)÷{[m^2-1-m+1)]/(m+1)}
=(m-1)/(m+1)÷{[m^2-m)]/(m+1)}
=(m-1)/(m+1)÷{m(m-1)/(m+1)}
=(m-1)/(m+1)*(m+1)/[m(m-1)]
=1/m=1/√3=√3/3供参考答案2:
条件不够吧