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求y=ln[1/(2x+1)] 的导数
求y=ln[1/(2x+1)] 的导数
发布时间:2021-02-24 09:09:36
求y=ln[1/(2x+1)] 的导数
网友回答
y=ln[1/(2x+1)]=-ln(2x+1)
y'=-2/(2x+1)
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