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求二阶导数y=ln(1+2x),求y''(0)!
求二阶导数y=ln(1+2x),求y''(0)!
发布时间:2021-02-24 09:09:32
求二阶导数y=ln(1+2x),求y''(0)!
网友回答
y=ln(1+2x)
y'=2/(1+2x)
y''=-4/(1+2x)²
======以下答案可供参考======
供参考答案1:
y=ln(1+2x),
一阶导数:y'=2/(1+2x)
二阶导数y''=-4/(1+2x)²
带入 x=0得
y''(0)=-41=-4
供参考答案2:
0自己代下 求二阶导数y=ln(1+2x),求y''(0)!(图1)
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