先化简,再求值:[x+2-(x-2分之5)]除以(x-2分之x-3),其中x=-2

网友回答

原式=[(x+2)(x-2)-5]/(x-2)]×(x-2)/(x-3)
=(x²-9)/(x-2)×(x-2)/(x-3)
=(x+3)(x-3)/(x-2)×(x-2)/(x-3)
=x+3=-2+3=1