(1)[(a5)3?(b3)2]5;(2)(x2?xm)3÷x2m(3);(4)(-a2)3+(-a3)2-a2?a3;(5)xm?(xn)3÷(xm-1?2xn-1

发布时间:2020-08-09 07:39:18

(1)[(a5)3?(b3)2]5;
(2)(x2?xm)3÷x2m
(3);
(4)(-a2)3+(-a3)2-a2?a3;
(5)xm?(xn)3÷(xm-1?2xn-1);
(6)(y-x)2(x-y)+(x-y)3+2(x-y)2?(y-x)
(7).

网友回答

解:(1)[(a5)3?(b3)2]5,
=(a15?b6)5,
=a75b30;

(2)(x2?xm)3÷x2m,
=x6+3m÷x2m,
=x6+m;

(3),
=1-+9-4,
=5;

(4)(-a2)3+(-a3)2-a2?a3,
=-a6+a6-a5 ,
=-a5;

(5)xm?(xn)3÷(xm-1?2xn-1),
=xmx3n÷(xm-1?2xn-1)
=x2+2n;

(6)(y-x)2(x-y)+(x-y)3+2(x-y)2?(y-x),
=(x-y)3+(x-y)3-2(x-y)3,
=0;

(7),
=-999×()99,
=-299.
解析分析:(1)(2)(5)首先利用幂的乘方运算法则去掉括号,然后利用单项式相乘的法则计算即可求解;
(3)利用有理数混合运算法则计算即可求解;
(4)(6)利用整式混合运算法则计算即可求解;
(7)利用积的乘方首先把题目变形化简,然后利用有理数的乘法法则计算即可求解.

点评:本题主要考查了有理数的混合运算、整式的混合运算,解题的关键是熟练掌握有关运算法则.
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