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如图,OB平分∠AOC,OC平分∠AOD,则:(1)∠AOB=______;∠AOC=______(2)∠AOD=______∠AOC=______∠DOB=____
如图,OB平分∠AOC,OC平分∠AOD,则:(1)∠AOB=______;∠AOC=______(2)∠AOD=______∠AOC=______∠DOB=____
发布时间:2020-08-25 03:07:27
如图,OB平分∠AOC,OC平分∠AOD,则:
(1)∠AOB=______;∠AOC=______
(2)∠AOD=______∠AOC=______∠DOB=______∠BOC.
网友回答
解:(1)∵OB平分∠AOC,
∴∠AOB=∠BOC;
∵OC平分∠AOD;
∴∠AOC=∠DOC;
故
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如图,矩形ABCD的对角线相交于点O,PD∥AC,PC∥BD,PD、PC相交于点P.猜想:四边形PCOD是什么特殊的四边形?请说明理由.
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如图,矩形ABCD的对角线相交于点O,PD∥AC,PC∥BD,PD、PC相交于点P.猜想:四边形PCOD是什么特殊的四边形?请说明理由.
如图,OB平分∠AOC,OC平分∠AOD,则:(1)∠AOB=______;∠AOC=______(2)∠AOD=______∠AOC=______∠DOB=____
某一物体运动情况或所受合外力的情况如图所示.其中(甲)图是某物体的位移-时间图象;(乙)图是某一物体的速度-时间图象;(丙)图表示某一物体的加速度-时间图象;(丁)图
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